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0.231x^2+2.600x-34.83=0
a = 0.231; b = 2.600; c = -34.83;
Δ = b2-4ac
Δ = 2.6002-4·0.231·(-34.83)
Δ = 38.94292
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2.600)-\sqrt{38.94292}}{2*0.231}=\frac{-2.6-\sqrt{38.94292}}{0.462} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2.600)+\sqrt{38.94292}}{2*0.231}=\frac{-2.6+\sqrt{38.94292}}{0.462} $
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